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**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

What is f(27)

http://i47.tinypic.com/16t8as.gif

Answer:

f(0)

f(1)

f(2)

f(3)

*Last edited by lakeheadca (2010-06-18 10:48:53)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 107,736

Hi lakeheadca;

I believe it is f(3)

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

Thank you Bobby,

Please can you show me how to solve it.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 107,736

Hi lakeheadca;

In the simplest way without using any math at all is the pattern cycles like this:

Draw a few more cycles of the curve yourself. You will see that 4 is the same as 0. 5 is the same as 1. 10 is the same as 2. After that you just have to line them up to see that 27 is in the same column as 3.

How did you do with the area and perimeter problem? Were you able to finish where I left you off?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**lakeheadca****Member**- Registered: 2010-01-31
- Posts: 37

you are a great help. very nice way to solve ... you made this problem amazingly simple.

Thank you,

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 107,736

Your welcome. I didn't make it simple, it is simple. The only reason it is, is because I have seen it before. I still get them wrong now and then but I am not surprised by the problem. Now that you have seen it you will do much better next time. I guarantee it.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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