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  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#1 2010-02-03 18:10:22

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

one group problem



somehow I feel that this problem's information is very insuffient, but I guess any set containing p+q can be eliminated.












the answer is e.

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#2 2010-02-04 11:11:05

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: one group problem


What I find a bit interesting is that the module structure of an abelian group doesn't add any information, but makes the above proposition more straightforward.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#3 2010-02-07 17:55:06

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: one group problem

sorry for the late reply,  what I dont understand is that it seems to be a group of under module something but it doesnt say anything

hmm that's an interesting proposition, first I doubted it because I overlooked the requirement that G is a group itself

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#4 2010-02-08 03:03:10

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: one group problem

Use Bézout's identity to prove the proposition.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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