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You are not logged in. #1 2009-09-03 22:35:51
Very hard question on asymptotics (maybe there is no answer yet)I have the following problem for which I cannot find an answer. I posted this same problem in "physicsforums" and "mathhelpforum" and still nobody was able to give me an anwser. I looked everywhere in the internet (journal, books, etc) and also found nothing. Maybe some of you guys can give me some hints. where C is a contour, f and g are analytic functions defined over C. What is the asymptotic approximation of the closed-form solution when t->infinity? In general you cannot use the classical methods from complex analysis like steepest descent or saddle point methods because these methods require for some h analytic. I found that there are solutions for general f when t is multiplying f, i.e., this is the general steepest descent. There are also solutions when Working with f, you'll find out that you can't cheat, e.g., won't help you. It only works for small values of t. So, for general f it seems that there is no general solution. What do you think? For a good reading on asymptotics, you can look at these books from google books http://books.google.es/books?id=_tnwmvHmVwMC&printsec=frontcover#v=onepage&q=&f=false http://books.google.es/books?id=xooq99A9anMC&printsec=frontcover#v=onepage&q=&f=false http://books.google.es/books?id=KQHPHPZs8k4C&printsec=frontcover#v=onepage&q=&f=false #2 2009-09-03 22:40:09
Re: Very hard question on asymptotics (maybe there is no answer yet)I've made a mistake in one part. Where I write "It only works for small values of t" should be "It only works for small values of z" #3 2009-09-04 11:17:04
Re: Very hard question on asymptotics (maybe there is no answer yet)Hi dannyv; Last edited by bobbym (2009-09-04 11:19:01) In mathematics, you don't understand things. You just get used to them. Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means. 90% of mathematicians do not understand 90% of currently published mathematics. #4 2009-09-04 22:36:05
Re: Very hard question on asymptotics (maybe there is no answer yet)Thanks for the link. First time I hear about Haar's method. #5 2009-09-04 22:37:35
Re: Very hard question on asymptotics (maybe there is no answer yet)Well, I will keep looking for a method, and If I find one I'll post it here. |