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**Gadodge****Guest**

Hi all,

I am working on some math problems, and there are two that I just can not get.

The first one is use the given information given to find the exact value of the trigonometric function.

cos Q=1/4, csc Q>0 Find sin Q/2

The second problem I have is solve the equation on the interval [0,2pi]

cos2x=sqrt3/2

If anyone can help me it would be greatly appreciated.

Thank you.

**juriguen****Member**- Registered: 2009-07-05
- Posts: 59

Hi

The first one I would say:

So every requirement holds.

The second:

Hope it helps!

Jose

Make everything as simple as possible, but not simpler. -- Albert Einstein

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**Gadodge****Guest**

Thanks so much. I have three other problems that I still can not get. Same like before solve the equation on the interval [0,2pi]

2sin^2x=sinx

(tanx+1)(cosx+1)=0

2cos^2x+sinx-2=0

Thanks for your help.

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi Gadodge;

the roots are:

*Last edited by bobbym (2009-08-22 12:52:16)*

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**juriguen****Member**- Registered: 2009-07-05
- Posts: 59

You're welcome

Jose

Make everything as simple as possible, but not simpler. -- Albert Einstein

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi gadodge;

gadodge wrote:

(tanx+1)(cosx+1)=0

These are the roots:

*Last edited by bobbym (2009-08-22 20:10:48)*

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**Gadodge****Guest**

Could you please explain how you got your answers. Thanks, I am still a little lost.

**soroban****Member**- Registered: 2007-03-09
- Posts: 452

Hello, Gadodge!

. .

.

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