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#1 2009-07-18 15:52:00

makaros
Guest

Help fiding Vertical Asymptote

Hi, I need help in finding vertical asymptote in particular question:

f(x)= 2x²-5/x+2, x≠ -2
a. Show that x= -2 is a verical asymptote.

Please explain how to find it..

Thank you

#2 2009-07-18 16:23:19

glenn101
Member
Registered: 2008-04-02
Posts: 108

Re: Help fiding Vertical Asymptote

makaros wrote:

Hi, I need help in finding vertical asymptote in particular question:

f(x)= 2x²-5/x+2, x≠ -2
a. Show that x= -2 is a verical asymptote.

Please explain how to find it..

Thank you

Hi Makaros,

vertical asymptotes appear when the denominator of a fraction = 0
so x+2=0
x=-2
is your asymptote:)


"If your going through hell, keep going."

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#3 2009-07-18 19:00:23

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Help fiding Vertical Asymptote

Hi Makaros;

glenn101 has correctly understood your meaning but you should put a parentheses around that denominator.

As written f(x)= 2x²-5/x+2 is

f(x)= 2x²-5/(x+2) is

what you want to say.

Last edited by bobbym (2009-07-18 19:03:08)


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#4 2009-07-19 02:03:44

makaros
Guest

Re: Help fiding Vertical Asymptote

In a book it says I have to use limit to find it... How to find Vertical asymptote using a limit?

Thanks)

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