Last edited by JaneFairfax (2009-07-16 06:28:10)
True, but that's not the main problem.
After your fix, we still have that P(B) = 2/3, so the "conclusion" still holds.
Why did the vector cross the road?
It wanted to be normal.
I dont see what the problem is, really (if not the minor one I pointed out). If you have two Black balls and one White ball in the bag, the probability of picking a Black ball is ⅔. If you have one Black ball and two other balls that can be either colour, the probability of picking a Black ball is also ⅔. There is nothing wrong with the probabilities of two different scenarios happening to be the same.
Last edited by JaneFairfax (2009-07-17 02:34:53)