Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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#2 2009-07-17 03:21:20
- JaneFairfax
- Legendary Member
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Re: Find the flaw
soroban wrote:
Last edited by JaneFairfax (2009-07-17 04:28:10)
#3 2009-07-17 03:45:37
- mathsyperson
- Moderator
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Re: Find the flaw
JaneFairfax wrote:
True, but that's not the main problem.
After your fix, we still have that P(B) = 2/3, so the "conclusion" still holds.
Why did the vector cross the road?
It wanted to be normal.
#4 2009-07-17 04:36:46
- JaneFairfax
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Re: Find the flaw
I don’t see what the problem is, really (if not the minor one I pointed out). If you have two Black balls and one White ball in the bag, the probability of picking a Black ball is ⅔. If you have one Black ball and two other balls that can be either colour, the probability of picking a Black ball is also ⅔. There is nothing wrong with the probabilities of two different scenarios happening to be the same.
Last edited by JaneFairfax (2009-07-18 00:34:53)