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You are not logged in. #1 20050722 23:44:01
Roots and RadicalsHi all. #2 20050723 01:04:03
Re: Roots and RadicalsI tried working backwards by squaring the answer, and found that you actually want to find to square root of: Why did the vector cross the road? It wanted to be normal. #3 20050723 03:43:11
Re: Roots and RadicalsHi thx for the reply. #4 20050723 03:48:50
Re: Roots and RadicalsOne more thing, is this a typo error agian or correct answer? #5 20050723 04:06:04
Re: Roots and Radicals√a x √b= √(a x b), so 4√x³y x 4√xy² = 4√(x³y x xy²) Why did the vector cross the road? It wanted to be normal. #6 20050723 07:50:20
Re: Roots and RadicalsAnother way to look at it is to think that a square root is also x^½ (x raised to the half power) "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman 