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#1 2006-03-29 10:04:14

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,552

Logarithm Formulas

Logarithm Formulas


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#2 2006-04-01 17:52:46

ganesh
Moderator
Registered: 2005-06-28
Posts: 15,152

Re: Logarithm Formulas

If

then


because


Character is who you are when no one is looking.

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#3 2006-04-04 04:11:31

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Logarithm Formulas

Last edited by Ricky (2006-04-04 04:11:44)


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#4 2006-08-05 13:53:15

Zhylliolom
Real Member
Registered: 2005-09-05
Posts: 412

Re: Logarithm Formulas

Logarithm of a Complex Number

where k is an integer.

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#5 2006-08-05 19:03:45

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: Logarithm Formulas

(which is log(xy) = log x + log y)

Last edited by Devanté (2006-08-05 19:10:52)

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#6 2006-09-05 03:15:28

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: Logarithm Formulas










Last edited by Devanté (2006-10-06 23:23:57)

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#7 2006-10-10 00:22:34

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: Logarithm Formulas

a1aa7d5f1f8b2b28b8366cf3688a7e1.gif

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#8 2009-01-02 06:03:12

random_fruit
Member
Registered: 2008-12-25
Posts: 39

Re: Logarithm Formulas

Can anyone explain Devante's post #7?  He says


This does not make sense to me, and seems to me to have exactly one value of x for which it is true.

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#9 2009-04-19 18:30:04

Shekhar
Member
Registered: 2009-04-19
Posts: 1

Re: Logarithm Formulas

Can anyone prove the following....
Given,
((2/3)^k)n = 1
Required to prove,
k is equal to log of n on base 3/2

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#10 2009-04-19 19:39:47

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,592

Re: Logarithm Formulas

Hi random_fruit;

It could be a quiz problem and I agree it appears  to have only 1 solution in R.

Last edited by bobbym (2009-04-19 19:44:38)


In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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#11 2009-06-09 21:04:36

noobard
Member
Registered: 2009-06-07
Posts: 28

Re: Logarithm Formulas

ganesh wrote:

If

then


because

hey ganesh jus a little thing
if we take  A and B of the same signs


here it should be


..

and in the other ones also... the argument has to be alwys positive


Everything that has a begining has an EnD!!!

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#12 2009-11-25 23:06:46

sekhar5955
Member
Registered: 2009-11-25
Posts: 1

Re: Logarithm Formulas

Hi Shekhar,
Here is the solution.
   ((2/3)^k)n = 1
⇒(2/3)^k = 1/n
⇒(2/3)^k = n-¹
Applying log on both sides.
⇒k log(2/3) = -log n
Multiplying (-) on both sides
⇒k log(2/3)-¹ = log n
⇒k log(3/2) = log n
∴ k = (log n)/(log (3/2))
⇒ k = log n base (3/2) 


Shekhar wrote:

Can anyone prove the following....
Given,
((2/3)^k)n = 1
Required to prove,
k is equal to log of n on base 3/2

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