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#27 2009-05-23 05:58:04
- bobbym
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Re: Kurre's Exercises
Hi Kurre;
Will you please post your solution to #7. I have been using summation by parts, abels transformation, exponential substitution to get a geometric sum and all the trig identities I know.
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#29 2009-05-23 13:27:34
- bobbym
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Re: Kurre's Exercises
Hi Bo Li;
Welcome to the forum.
You forgot to enclose your latex between {math}{/math} with [ replacing { and ] replacing } so it looks like this:
Anyway, how does this prove # 14
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#31 2009-05-23 22:31:08
- Kurre
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Re: Kurre's Exercises
kean wrote:
sure！ it's right
\sum_{k=1}^n \zeta_k^m =0
it does not hold for all m and n
#32 2009-05-23 22:37:58
- bobbym
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Re: Kurre's Exercises
Thanks Kurre for providing the answer to #7.
In mathematics, you don't understand things. You just get used to them.
Probability is the most important concept in modern science, especially as nobody has the slightest notion what it means.
90% of mathematicians do not understand 90% of currently published mathematics.
#33 2009-05-25 19:40:00
- Kurre
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Re: Kurre's Exercises
#15let k,n be positive integers, a a nonzero real, k<n+1 . Show that:
both with real analysis and by using residue calculus
edit: i did a mistake so i dont know if its possible to do this using residues, but that does not mean it must be impossible
Last edited by Kurre (2009-05-26 04:43:09)