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hey im just goin through old tutorials in preperation for my exam and came across this question
Find the vector equation of the line tangent to the graph of r(t) at the point P0(0,−1, 1/4 ) on the curve.
my lecturer gave this soloution
Solution: The point P0(0,−1, 1/4 ) on the curve corresponds to t = 1. We find
r0 = r(1) = −j +1/4k , v0 =dr/dt(1) = i − j +1/2k .
Thus the tangent line equation is
r = r0 + (t − 1) v0 = (t − 1) i − t j +1/2(t −1/2) k .
i get all of it except the bit where he finds v0 and was wondering if some1 could explain it to me
thanx
Theres only 10 type of people in the world
Those that understand binary
And those that dont
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