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#1 2009-04-14 20:19:36

smiyc86
Member
Registered: 2009-03-19
Posts: 78

few quants problems

Milan uses an escalator at the railway station.

If he runs up 8 steps of the escalator, then it takes him 40.0 seconds to reach the top of the escalator.

If he runs up 15 steps of the escalator, then it takes him only 22.5 seconds to reach the top of the escalator.

How many seconds would it take Milan to reach the top, if he did not run up any steps of the escalator at all? Also, how many steps are visible, when the escalator is stationary?


I love Maths and Music ... dunno which more wink

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#2 2009-04-15 00:50:55

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: few quants problems


Why did the vector cross the road?
It wanted to be normal.

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#3 2009-04-15 22:23:59

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

smile correct


I love Maths and Music ... dunno which more wink

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#4 2009-04-15 22:26:55

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

(sinx)^4-(sinx)^5-(cosx)^5 = 2

solve for x


I love Maths and Music ... dunno which more wink

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#5 2009-04-16 23:53:43

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: few quants problems

Hi smiyc86;

Here is a quick and very ugly way to get the real roots of   (sinx)^4-(sinx)^5-(cosx)^5 = 2

First I notice that big 2 on the rhs and guess that one of the extrema of sin(x) and cos(x) are the answer. We have:






Just trying the first one yields (-1)^4 - (-1)^5 - 0 which equals 2 so x = -π/2 is one solution. Since sin is periodic


with c=0,1,2,3... are all solutions.

There are also complex solutions but I could not get them without resorting to an iterative method so I left them out.

bobbym

Last edited by bobbym (2009-04-17 00:06:33)


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#6 2009-04-21 20:19:50

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

hi bobbym,

very good observation up

and in fact your answer is correct ... smile

I would give a slightly better way

rewrite the equn as

(sin x)^4 - 2 = (sin x)^5 + (cos x)^5

now the max value of LHS is -1
and the min value of RHS = -1

thus if the equation holds true ... both the sides are got to be equal to -1

hence u can come to the solution ...

Last edited by smiyc86 (2009-04-21 20:22:33)


I love Maths and Music ... dunno which more wink

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#7 2009-04-21 20:32:44

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: few quants problems

Thanks for providing me with another way to do it.


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#8 2009-04-21 21:17:41

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

up


I love Maths and Music ... dunno which more wink

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#9 2009-04-22 00:18:28

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

# 3

Find the smallest number N which has the following properties:
its decimal representation has 6 as the last digit.

If the last digit 6 is erased and placed in front of the remaining digits, the resulting number is four times as great as the original number N.


I love Maths and Music ... dunno which more wink

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#10 2009-04-22 03:51:29

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: few quants problems

Hi smiyc86;

solution to #3

solution

Last edited by bobbym (2009-04-22 03:53:16)


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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#11 2009-04-23 18:14:48

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: few quants problems

nice .... up


I love Maths and Music ... dunno which more wink

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