Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2009-03-26 02:53:50

Avva
Member
Registered: 2009-02-25
Posts: 41

smilarity

In the quadrilateral ABCD , ‹B is bisected by a bisector intersecting  AC(line segment) at E. F is the point of intersection of AD(line segment) with the ray EF drawn parallel to CD(line segment). If AB=9cm , BC=6cm , EF=2.4cm< FIND the length of CD(line segment).


plz attach the drawing to your answer.

Offline

#2 2009-03-26 03:16:01

Jai Ganesh
Administrator
Registered: 2005-06-28
Posts: 45,956

Re: smilarity

I have attached a drawing....Hope someone asnwers soon!!!


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

#3 2009-03-26 03:40:53

Avva
Member
Registered: 2009-02-25
Posts: 41

Re: smilarity

TX for ur drawing u forgot just to put parallel & bisector signs.

Last edited by Avva (2009-03-26 03:48:19)

Offline

#4 2009-03-26 16:38:12

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: smilarity

as ganesh has already provided the diagram ... am providing the solution ...

AE/AB = EC/BC .... bisector theorem ...

from this we get ...

EC/AE = 2/3
=> AC/AE = 5/3 ... AC = AE + EC

now, AEF ~ ACD

hence, CD/EF = AC/AE

CD = 4

wink


I love Maths and Music ... dunno which more wink

Offline

#5 2009-03-26 22:28:04

Avva
Member
Registered: 2009-02-25
Posts: 41

Re: smilarity

many TX for u both

Offline

#6 2009-03-26 22:33:18

smiyc86
Member
Registered: 2009-03-19
Posts: 78

Re: smilarity

pleasure wink


I love Maths and Music ... dunno which more wink

Offline

#7 2009-03-27 02:07:03

chelsea-ann x
Guest

Re: smilarity

its wel good hard tho i really struggle with maths asit is my worse subject

Board footer

Powered by FluxBB