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#1 2008-04-27 19:25:18

ROBBYM
Member
Registered: 2008-04-24
Posts: 10

continuous

show the function f:R->R

when x does not equal 4
                        8 when x equals 4

is continuous on R

Last edited by ROBBYM (2008-04-27 19:28:42)

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#2 2008-04-27 19:28:04

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: continuous

its not continuous, x cant take the value 4

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#3 2008-04-27 19:54:22

ROBBYM
Member
Registered: 2008-04-24
Posts: 10

Re: continuous

So if i re-write it like this then


isn't this continuous if x does not equal 4

but if x equals 4  then f(x)=8 which is not continuous for all real values of x

therefore the function is not continuous????

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#4 2008-04-27 22:38:36

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: continuous

The function is continuous. As you said, for x≠4 the function is equal to x+4. The function is defined piecewise, so you don't need to worry about division by 0 because it treats x=4 as a special case anyway.

As x gets close to 4, f(x) gets close to 4+4 = 8. f(4) is defined to be 8, and so there is no discontinuity at x=4. There is obviously no discontinuity anywhere else either, and so f(x) is continuous.


Why did the vector cross the road?
It wanted to be normal.

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#5 2008-04-27 23:16:22

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: continuous

f(x) is continuous at a point a if and only if the following conditions hold:
(i) F(x) is defined at x = a
(ii) F(x) → f(a) as xa (both from the left and from the right)

Check that your function satisfies the two conditions above.

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#6 2008-04-28 03:46:00

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: continuous

oh yea, my bad,sorry left limit = right limit...

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