
 ganesh
 Moderator
Take the challenge.....
Take the challenge..... The first one to answer this question gets 100 clean jokes in his or her mailbox, free................. In a gettogether, every person present shakes hand with every other person once...... If there are 91 handshakes in all, how many people attended the party? Don't take more than 5 minutes for answering this.
Character is who you are when no one is looking.
 MathsIsFun
 Administrator
Re: Take the challenge.....
Let me see
If there was only one person, there would be no handshake If there were two then there would be one handshake (AB) With three people there would be three handshakes (AB, AC, BC) With four there would be be (AB, AC, AD, BC, BD, CD) = 6 With five there would be be (AB, AC, AD, AE, BC, BD, BE, CD, CE, DE) = 10
*brnnggggg*
Oh, no, my five minutes is up!
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman
Re: Take the challenge.....
MathsIsFun may have run out of time, but he did show everyone an important pattern. With n people, the number of handshakes would be the (n1)th triangular number.
This means that with 91 people, there would be the 90th triangular number of handshakes, which is
(90*91)/2=4095 handshakes.
Why did the vector cross the road? It wanted to be normal.
 Roraborealis
 Super Member
Re: Take the challenge.....
I wish I got here quicker......
School is practice for the future. Practice makes perfect. But  nobody's perfect, so why practice?
 MathsIsFun
 Administrator
Re: Take the challenge.....
You can still have a go, Rora, just time yourself.
I am obviously not quick enough *sob*
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman
 ganesh
 Moderator
Re: Take the challenge.....
Well, the answer is 14. Each person would shake hands with thirteen others, resulting in 14 x 13 = 182 but a handshake involves two people.... divide that by 2, you get 91...
the way to solve this problem is n(n1) = 91 x 2 = 182 Solve the equation, you get n=14.
My 100 clean jokes remain with me, ha!
Character is who you are when no one is looking.
 Roraborealis
 Super Member
Re: Take the challenge.....
Nooooooo! Please share them! Spread the joy!
School is practice for the future. Practice makes perfect. But  nobody's perfect, so why practice?
 ganesh
 Moderator
Re: Take the challenge.....
Please visit my 'Lots of Jokes' page.... at http://www.geocities.com/ganesh91569
Character is who you are when no one is looking.
Re: Take the challenge.....
I feel really stupid now. I didn't read the question properly at all! Oh well, at least that happened here instead of in an exam...
P.S. Brilliant avatar!
Last edited by mathsyperson (20050701 01:09:01)
Why did the vector cross the road? It wanted to be normal.
 Zach
 Super Member

Re: Take the challenge.....
[ Insert cruel and sadistic, yet sharply witty, comment here to annoy Rora to the full. ]
Boy let me tell you what: I bet you didn't know it, but I'm a fiddle player too. And if you'd care to take a dare, I'll make a bet with you.
 MathsIsFun
 Administrator
Re: Take the challenge.....
Oh yeah, mathsyperson, it was good until you supersized it! LOL
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman
 ganesh
 Moderator
Re: Take the challenge.....
We know that at 40 degrees, degree centigrade is equal to degree Fahrenheit. Can you guess at what temperature degree Fahrenheit would be equal to Kelvin?
Character is who you are when no one is looking.
Re: Take the challenge.....
1 degree Fahrenheit = 255.927778 Kelvin 1 Kelvin = 457.87 degrees Fahrenheit
 Roraborealis
 Super Member
Re: Take the challenge.....
Woah......what's Mr. Potato head doing on front of a box of chips?
School is practice for the future. Practice makes perfect. But  nobody's perfect, so why practice?
 MathsIsFun
 Administrator
Re: Take the challenge.....
Roraborealis wrote:Woah......what's Mr. Potato head doing on front of a box of chips?
Yeah, bit of a far out marketing concept, hey?
But on with the puzzles.
Kelvin is just Celsius shifted upwards by 273.16, the idea being that absolute zero is 0° K. This would make room temperature about 293°.
Todays forecast: fine, sunny with tops around 295°
So, convert from °K to °C, then from °C to °F. Ohhh, my poor brain hurts ... someone help me ....
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman
Re: Take the challenge.....
°C=K273.15 °F=1.8°C+32 ∴ °F=1.8(K273.15)+32
Ganesh wants to know when these are the same, so solve y=1.8(y273.15)+32. Expand the brackets: y=1.8y491.67+32 Combine the numbers: y=1.8y459.67 Add 459.67y to both sides: 0.8y=459.67 Solve: y=575°F/K to the nearest unit. We can't really be more accurate than that because we don't know the exact value of how much bigger K is than °C.
To keep with the theme of temperature, if you have one bucket of water at 30°C and one at 30°F and drop a ball (that sinks!) into both, which will reach the bottom first?
Last edited by mathsyperson (20050701 18:26:24)
Why did the vector cross the road? It wanted to be normal.
 ganesh
 Moderator
Re: Take the challenge.....
mathsyperson is correct.....neat work.... the exact value is 574.5875 and we take degrees centigrade plus 273..15 as Kelvin temperature.... Coming to his question, the bucket of water would at 30 degrees Fahrenheit would have frozen at thirtytwo degree F! so the ball wouldn't sink in the bucket of water at 30 deg f!!!
Character is who you are when no one is looking.
