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#1 2008-01-14 15:45:28

LuisRodg
Real Member
Registered: 2007-10-23
Posts: 322

Simple but I guess im dumb.

Was just doing some Calculus homework in which I got the answer to be:

[0.5e^(2ln2)] - 0.5

What property do I use to simplify e^(2ln2)?

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#2 2008-01-14 17:32:23

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Simple but I guess im dumb.

I checked in the formula's section of this forum
and this wasn't in it explicitly, but might be
implied from 2 other equations.
This MIGHT be right:

Here are two formulas similar to those I found.

n ln(m) = ln(m^n)
where m may be restricted to values above zero??

e^(ln(s)) = s, and s may have to be above zero??

Last edited by John E. Franklin (2008-01-14 17:43:51)


igloo myrtilles fourmis

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#3 2008-01-15 07:05:18

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Simple but I guess im dumb.

I see it in a slightly different way, but I get the same answer as John.
Using laws of powers, e^(2ln2) = e^(ln2 x 2) = (e^ln2)^2.

Clearly, e^ln2 = 2, and so the answer is 2^2 = 4.


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#4 2008-01-15 07:09:49

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: Simple but I guess im dumb.

which continuing gives 1.5 for the full expression


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