Math Is Fun Forum

RESPEK

Guest

HELP! quick reply pls(trigo)

how to find B in the equation:
cosA-(sinA)^(1/3)=Rcos(A+B) 
thanks!

Jai Ganesh

Administrator

Registered: 2005-06-28

Posts: 46,340

Re: HELP! quick reply pls(trigo)

cosA-(sinA)^(1/3)=Rcos(A+B)

Last edited by Jai Ganesh (2007-12-29 17:17:55)

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RESPEK

Guest

Re: HELP! quick reply pls(trigo)

thanks dude, but anyway to find B in radians?

RESPEK

Guest

Re: HELP! quick reply pls(trigo)

and the sinA^(1/3) is cube root of sinA, thanks

luca-deltodesco

Member

Registered: 2006-05-05

Posts: 1,470

Re: HELP! quick reply pls(trigo)

the unit of B is dependant on your calculator, if you have it set to radians, it will calculate the inverse cosine to radians, if you have it set to degrees, it will calculate the inverse cosine to degrees.

also, ganesh you should really have it written as

what you had would technically be sin(A^1/3) not (sinA)^1/3

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RESPEK

Guest

Re: HELP! quick reply pls(trigo)

but wat i need is the exact value of B, so im not sure how to go about doing that with the equation