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#2 2007-12-23 06:35:23
- mathsyperson
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Re: solve inequality
Why did the vector cross the road?
It wanted to be normal.
#4 2007-12-23 22:57:24
- mathsyperson
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Re: solve inequality
Sorry, I'm not sure what you're getting at.
6/10 is a solution and is in my solution set, so there's no contradiction.
If you're hinting at a more elegant method of reaching the answer, I'm afraid I don't get that either.
Why did the vector cross the road?
It wanted to be normal.
#5 2007-12-23 23:56:10
- JaneFairfax
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Re: solve inequality
Perhaps he’s hinting that your solution isn’t wholly correct. x = 6⁄10 is NOT a solution. Also, you can’t have x = 1. What is logarithm to base 1, anyway?
Anyway, logx where x < 1 problematic. If x < 1, then you actually have logxy > 0 when y < 1 and logxy < 0 when y > 1. With this in mind, I think you’ll find that not only
is invalid but also
is a solution set as well.
Last edited by JaneFairfax (2007-12-24 00:00:39)
#6 2007-12-24 00:42:59
- mathsyperson
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Re: solve inequality
Ah, fair enough. I made too many assumptions in the first step.
Why did the vector cross the road?
It wanted to be normal.