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#1 2007-12-16 08:07:23

henryzz
Member
Registered: 2007-06-03
Posts: 14

Finding algebraic factors of (2^n)+-1

what are the methods for finding algebraic factors of (2^n)+-1

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#2 2007-12-16 20:38:30

Jai Ganesh
Administrator
Registered: 2005-06-28
Posts: 45,969

Re: Finding algebraic factors of (2^n)+-1

Do you mean prime factors?


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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#3 2007-12-17 01:24:06

henryzz
Member
Registered: 2007-06-03
Posts: 14

Re: Finding algebraic factors of (2^n)+-1

no i mean like (2^2n)-1 = ((2^n)-1)*((2^n)+1)

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#4 2007-12-17 02:10:17

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: Finding algebraic factors of (2^n)+-1

Remember that 2^n is just some number, so for 2^n + 1, you can't break it up into real factors.  2^n-1 however can easily be broken up as long as n is even since it is a difference of two squares.  If it's not even, then you can still do this but the term 2^n/2 will not be an integer, as is usually wanted when factoring.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#5 2007-12-19 05:18:13

henryzz
Member
Registered: 2007-06-03
Posts: 14

Re: Finding algebraic factors of (2^n)+-1

what i want to know is there any more method of factoizing them

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#6 2007-12-19 05:34:21

Daniel123
Member
Registered: 2007-05-23
Posts: 663

Re: Finding algebraic factors of (2^n)+-1

?

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