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ABCD is a cyclic quadrilateral, with side
AD= d
where d is the diameter of the circle. AB= a
BC= a
and CD= b
If a, b and d are integers a ≠ b
(a)prove that d cannot be a prime number
.
(b)determine the minimum value of d.
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let O be the center of circle
join AC and OB let they meet at E.
Now triangle ABO and triangle BCO are congruent. and it can be proved that AC and BO are perpendicular.
Now
equaling (1) and (2) and simplifing
Last edited by gyanshrestha (2007-11-22 22:40:22)
http://gyan.talkacademy.com.np
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