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Hi all,
i need some help, Here the question:
1. What is the average (arithmetic mean) of 8, 7, 7, 5, 3, 2, and 2?
a. 3 4/7
b. 4 5/6
c. 4 6/7
d. 5
e. 6 4/5
I think the answer is A but the correct answer is C, i dont understand, please to explain for me.
2. If F (4) = 0 and f (6) = 6, which of the following could represent f (x)?
a. 2/3x - 4
b. x + 2
c. x - 4
d. 3/2x + 6
e. 3x - 12
The correct is E. I dont understand, please help
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for the first part to find the mean just add all the numbers together like this:
8 + 7 + 7 + 5 + 3 + 2 + 2 = 34 then you divide that answer by the amount of terms or the amount of numbers, which is 7. so then it would look like this: 34/7 which simplifys down to 4 6/7.
For the second problem think of f(x) to be just another way to put down a variable, "y"
so f(x) would just be y. so then for f (4) = 0 means that some function gives out the value of 0 when y = 4 and the second part f (6) = 6 means that the same function gives out a 6 when y = 6. so then you know that the function has to give out a 0 when y = 4, so then you can just put in 4 for all the x's untill one of them gives out the value of 0, in this case it is 3x - 12 where
3*4 - 12, 12 - 12, 0 , so that equation works for the value of 4. then you check it with the other part where y = 6 so 3*6 - 12, 18 - 12, which turns out a 6. so the equations works for both the values so it is the right answer.
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for the first part to find the mean just add all the numbers together like this:
8 + 7 + 7 + 5 + 3 + 2 + 2 = 34 then you divide that answer by the amount of terms or the amount of numbers, which is 7. so then it would look like this: 34/7 which simplifys down to 4 6/7.
i dont understand: your mean 46/7 or 4*6/7 but 4*6= 24 please explain again for me. Thanks
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What I meant is 4 and 6\7 as a mixed fraction simplyfied from the improper fraction of 34\7 where the 34 is divided by 7, 4 equal times with 6\7 left over, so it 4 and 6\7
Last edited by im really bored (2005-06-19 14:38:06)
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i see now. thank a lot
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