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#1 2007-10-20 01:15:04
- Identity
- Member
- Registered: 2007-04-18
- Posts: 934
inverse functions
Find the inverse function of
Working:
My question is... do you say the inverse function is
? Because that isn't really a function (it doesnt' pass the vertical line test). Or should I split it up to say or . Or does this vary between people?Offline
#2 2007-10-20 01:28:01
- mathsyperson
- Moderator
- Registered: 2005-06-22
- Posts: 4,900
Re: inverse functions
f(x) just doesn't have an inverse.
Not if its in R, anyway. Restricting the domain to R[sup]+[/sup] would work.
Why did the vector cross the road?
It wanted to be normal.
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#3 2007-10-20 04:18:45
- Identity
- Member
- Registered: 2007-04-18
- Posts: 934
Re: inverse functions
ok thanks!
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