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#1 2007-09-18 21:17:02

notagenius
Member
Registered: 2007-09-18
Posts: 2

problem

i gotta find an integer that starts with 7 and if that 7 is put at the end of the number it becomes 1/5 of the first number!!

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#2 2007-09-18 21:40:32

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: problem

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#3 2007-09-18 22:09:31

notagenius
Member
Registered: 2007-09-18
Posts: 2

Re: problem

Jane, could you please tell me if there's a formula for it, so that it can be done without a calculator? I only got to the fact that every integer ending with 7 when multiplied has to end with 85 or 35, and if i want the number to begin with 7, i gotta have it start with 14... my brain is kinda stuck

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#4 2007-09-18 23:01:08

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: problem

The first number is 5 times the second number. So the first number is a multiple of 5 and so must end in …0 or …5. However, the second number is odd (it ends with in …7) and so the first number can’t end in …0. Hence it ends in …5 and so the second number must end in …57.

5 × 57 = 285

∴ the first number ends in …285.

5 × 2857 = 14285

∴ the first number ends in …14285.

5 × 142857 = 714285

Bingo!

Last edited by JaneFairfax (2007-09-20 09:26:35)

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#5 2007-09-19 08:21:05

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: problem

I found another one but no 7 in this one:
1020408.16 x 5 = 50102040.8
Treat your calculator like a toy and keep trying
numbers that are just a little bit different from
the last and see if you can figure out how things
are changing.  Sometimes jump a lot if you
want something new.


igloo myrtilles fourmis

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