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hey everyone!
can some please check this for me. Thank you
lim x-->0
xcosx / sin2x = 0/0
-xsinx+cosx / 2cos2x = 0+1/2.1 = 1/2
is this correct?
Flawlessly.
Why did the vector cross the road?
It wanted to be normal.
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hey everyone!
can some please check this for me. Thank you
lim x-->0
xcosx / sin2x = 0/0
-xsinx+cosx / 2cos2x = 0+1/2.1 = 1/2
is this correct?
Yes, though using L'Hopital is a bit of "over-kill". Rewrite that as
If you know the derivative of sin x you certainly should recognize that the limit of is 1.rootz wrote:hey everyone!
can some please check this for me. Thank you
lim x-->0
xcosx / sin2x = 0/0
-xsinx+cosx / 2cos2x = 0+1/2.1 = 1/2
is this correct?
Yes, though using L'Hopital is a bit of "over-kill". Rewrite that as
If you know the derivative of sin x you certainly should recognize that the limit of is 1.
Oops I meant, of course,
which will give 1/2 as limit. Is there anyway to edit posts on this forum?Hi HallsOfIvy ... sign up!
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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