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#1 2007-04-27 19:37:35

Finch.
Member
Registered: 2007-04-27
Posts: 2

Simplifying an Equation

Hey all I've got this equation:

X = (L / (P ^ N)) - ((L / (P ^ N)) * (1 - (G / L)))

And it looks like you should be able to simplify it, but my maths skills aren't quite up to the task. If anyone could show me how to simplify it that'd be great!

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#2 2007-04-27 21:58:31

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Simplifying an Equation

Is

the original equation?
In that case:



If you have further questions about simplification feel free to ask.

Last edited by Identity (2007-04-27 21:59:34)

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#3 2007-04-27 22:03:30

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,711

Re: Simplifying an Equation

Nicely formatted, Identity.


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#4 2007-04-27 22:11:37

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Simplifying an Equation

Thanks, I've had some experience with Latex

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#5 2007-04-27 23:42:31

Finch.
Member
Registered: 2007-04-27
Posts: 2

Re: Simplifying an Equation

Thanks for the reply! That's exactly what I was after, but unfortunately I wrote the equation wrong. tongue It should have been:

(L / (P ^ N)) - (L / (P ^ N) - L) * (1 - G / L)

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#6 2007-04-28 00:12:51

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Simplifying an Equation

So it should look like this?

If so,



Why did the vector cross the road?
It wanted to be normal.

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#7 2007-04-28 00:16:28

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Simplifying an Equation

Finch. wrote:

Thanks for the reply! That's exactly what I was after, but unfortunately I wrote the equation wrong. tongue It should have been:

(L / (P ^ N)) - (L / (P ^ N) - L) * (1 - G / L)

Lol:P




This stage is as fully simplified as it really needs to be, but if you want it over the same denominator, here are some other variations:

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#8 2007-04-28 00:35:14

Finch.
Member
Registered: 2007-04-27
Posts: 2

Re: Simplifying an Equation

Thanks! That's exactly what I was after.

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