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y' = x^2+y^2 , y(0) = 0
PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I have no idea how to solve it but I found the general solution on the Internet. Your equation is a so-called special Riccati equation, and my word! The general solution involves Bessel functions of both the first and second kinds! Well, maybe the particular solution youre looking for is simpler but, even so
Here it is, if you want to make sense of it:
http://eqworld.ipmnet.ru/en/solutions/ode/ode0106.pdf (PDF document)
It seems that the general Riccati equation is easier to solve than the special Riccati equation.
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Indeed differential equations can get frigh...tening!
X'(y-Xβ)=0
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