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#1 2007-02-02 04:23:20

jxharmon
Member
Registered: 2007-01-08
Posts: 104

geometry help!

length of a rectangle is 2 inches mor than twice its width. if the perimeter of the rectangle is 34 inches find the demensiions of the rectangle; 2(length +width) =34; 2(2+2x)+x=34; 4+6x=34;6x=30; x=5 if that is right I am now beside myself in other words I am lost as to how to find the solutiondunno

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#2 2007-02-02 05:02:35

pi man
Member
Registered: 2006-07-06
Posts: 251

Re: geometry help!

You're doing great.   X is your width so your rectangle has a width of 5 and a lenght of 2 + 2X = 12.    To doublecheck: 2 times the width + 2 times the lenght = 2*5 + 2*12 = 10+24 =34.

By the way, there's one mistake in your equations.   Since you came up with the right answer, it must have been a typo.  2(2+2x)+x=34 should be 2(2+2x)+2x=34

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#3 2007-02-02 05:23:48

jxharmon
Member
Registered: 2007-01-08
Posts: 104

Re: geometry help!

Thanks guess I just got lost but it makes sense now.

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