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What is the common method to work out a fraction with three stages?
I have 6/x and I've worked out x=-3/2 :
6/(-3/2)
I may have the wrong value for x, but I'd still like to know a good method for doing this ![]()
Thanks in advance.
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Well,
Now, if you remember back to basic division, to divide you must reciprocate the denominator and multiply it to the numerator:
Last edited by Toast (2007-01-28 23:03:33)
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One way to think about it is with fraction multiplication - when you divide by a/b, it's equivalent to multiplying by b/a (i.e. the inverse of a/b).
So, your problem poses how to find:
which is the same as doing:
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Okay, that's brilliant and I understand how to do it! Thanks.
Could you have a look at my working out here? I'm not sure where I have gone wrong:
Find the points where the given line meets the given curve:
2x - 5y + 17 = 0 meets xy = 6
Firstly I get y on its own:
5y = 2x + 17 y = 6/x
y = 2/5x + 17/5
Now I can place the two side by side:
2/5x + 17/5 = 6/x
Now I balance and collect all the terms:
2/5x^2 + 17/5x = 6
2x^2 + 17x = 30
2x^2 + 17x - 30 = 0
Now I find two numbers whose sum is 17 and product is 2*-30 (or -60). These two numbers are +20 and -3, I re-write the quadratic:
2x^2 - 20x + 3x - 30 = 0
Now I take out the common factor of the first two numbers, then the second two numbers making sure that both sets of brackets are the same:
2x^2 - 20x + 3x - 30 = 0
2x(x-10) + 3(x-10) = 0
This leaves me with:
(2x+3)(x-10)
So x=10 or x=-3/2
I substitute these values into y=6/x to give me
y=6/10 and y=6/(-3/2)=-4
So the answer should be that the line intersects the curve at (10, 6/10) and (-3/2, -4). My book gives the answers with the signs reversed!:
(3/2, 4) and (-10, -3/5)
Whose signs are backwards?
Edit:
These two numbers are +20 and -3, I re-write the quadratic:
2x^2 - 20x + 3x - 30 = 0
My signs are wrong
Thanks again!
Last edited by rickyoswaldiow (2007-01-28 23:33:06)
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