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Hi,
I need to find a function that satisfies this rule:
As x approaches 0, y approaches a set limit
x must be able to equal 0 at which time y will equal its set limit
so if y's limit is 10; then the closer to zero x is, the closer to 10 y is.
Thanks for any help anyone can give
Maybe I'm making a mistake here, but couldn't you just do y=K, where K is the set limit that y needs to be at y=0?
Failing that, how about y=x+K?
Why did the vector cross the road?
It wanted to be normal.
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Hmmm. when x-->0 , f(x)--->c , x=0, f(0)=c ,The same as mathsyperson , suggest y=x+K
Numbers are the essence of the Universe
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I prefer y = x^2 + 10, just because it's more curvy and junk.
igloo myrtilles fourmis
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Well, you could have pretty much any function you wanted in there, as long as it was continuous and you added an appropriate constant on there so that y approached the correct limit at x=0.
We could just as easily have y = cosh[(3x+7)²]+K, or whatever else we could possibly think of.
Why did the vector cross the road?
It wanted to be normal.
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y=1/(x+1) , hehe
Numbers are the essence of the Universe
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