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#1 2007-01-23 21:30:31

George
Guest

help to find a function

Hi,

I need to find a function that satisfies this rule:

As x approaches 0, y approaches a set limit
x must be able to equal 0 at which time y will equal its set limit

so if y's limit is 10; then the closer to zero x is, the closer to 10 y is.

#2 2007-01-23 21:31:51

George
Guest

Re: help to find a function

Thanks for any help anyone can give

#3 2007-01-23 21:56:40

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: help to find a function

Maybe I'm making a mistake here, but couldn't you just do y=K, where K is the set limit that y needs to be at y=0?

Failing that, how about y=x+K?


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It wanted to be normal.

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#4 2007-01-24 13:13:59

Stanley_Marsh
Member
Registered: 2006-12-13
Posts: 345

Re: help to find a function

Hmmm. when x-->0 , f(x)--->c  , x=0, f(0)=c    ,The same as mathsyperson , suggest y=x+K


Numbers are the essence of the Universe

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#5 2007-01-24 15:08:16

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: help to find a function

I prefer y = x^2 + 10, just because it's more curvy and junk.


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#6 2007-01-25 00:14:36

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: help to find a function

Well, you could have pretty much any function you wanted in there, as long as it was continuous and you added an appropriate constant on there so that y approached the correct limit at x=0.

We could just as easily have y = cosh[(3x+7)²]+K, or whatever else we could possibly think of.


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It wanted to be normal.

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#7 2007-01-26 10:25:18

Stanley_Marsh
Member
Registered: 2006-12-13
Posts: 345

Re: help to find a function

y=1/(x+1) , hehe


Numbers are the essence of the Universe

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