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IF cosecθ-sinθ=p,secθ-cosθ=q
PROVE THAT p²q²(p²+q²+3)=1
Last edited by soha (2007-01-11 21:09:17)
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therefore
and
therefore
and
and so
Call the above equation (1)
Now
This you can see by directly multiplying out the cubic, collecting like terms and remembering that c^2 + s^2 = 1
So we have:
and so
Therefore, from equation (1) we have:
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