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The problem with X=.99999999...
When minus'ing the X, frim both side, you minus X,
plug in X on BOTH sides,
10(.99999....) - .999999 = 9.999999 - .9999999
it then comes out correctly, it is the same instance as if a=b
and you divide by (a-b) to make 1=0.
It is a trick of the variables and when correctly put with numbers instead of letters makes everything correct.
i dont quite understand what you're doing here to get 1=0?
The Beginning Of All Things To End.
The End Of All Things To Come.
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Recurring numbers have several rules to them.
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If a = b, then a - b = 0, and division by zero is not valid here.
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I do wanna argue that the approach of 10*0.999... thing does imply the last "9" equals the second last "9". And sorry I don't quite agree with the so-called rules designed to cover a bunch of paradoxies created by the original concept.
X'(y-Xβ)=0
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And the proof does imply ∞+1=∞ regarding how "many" "9"s
X'(y-Xβ)=0
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Not this again.. Please search the forum, we have plenty of posts on this
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And sorry I don't quite agree with the so-called rules designed to cover a bunch of paradoxies created by the original concept.
Paradox? I'm sorry, but what paradox? The only thing you have said so far is that stating .999... = 1 requires a guess.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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And sorry I don't quite agree with the so-called rules designed to cover a bunch of paradoxies created by the original concept.
Paradox? I'm sorry, but what paradox? The only thing you have said so far is that stating .999... = 1 requires a guess.
Great point, since you finally keep it in mind. I'll explore the other paradoxes soon. Wait for me
X'(y-Xβ)=0
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