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#1 2006-11-01 05:21:55

unique
Member
Registered: 2006-10-04
Posts: 419

solve

solve the following equation if

0degrees < θ < 360degrees
               -


sin θ = - (sqrt(3) / 2)

Edited to turn 0 into θ

Last edited by mathsyperson (2006-11-01 09:00:44)


Desi
Raat Key Rani !

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#2 2006-11-01 09:04:55

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: solve

I made an edit to your post because I think that's most probably what you meant. Saying sin 0, where 0 is a variable, causes lots of confusion.

Anyway, the question isn't too hard. If sin θ = -√3/2, then θ = sin-¹ (-√3/2).

We know that sin 60° = √3/2, and we can use that to deduce that sin -60° = -√3/2.

Using the CAST diagram, we can then see that the values of θ within the domain that work for this equation are 240° and 300°.


Why did the vector cross the road?
It wanted to be normal.

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