You are not logged in.
Pages: 1
The sum of 6 times jacks age and 5 times larrys age is 63. Jack is 1 year less than 3 times as old as larry. find each of their ages. :)
It says to use two equations with two variables to solve!!
please help, im really having troble with these kind of problems.
J := jacks age
L := larrys age
"The sum of 6 times jacks age and 5 times larrys age is 63" means:
6J + 5L = 63
"Jack is 1 year less than 3 times as old as larry" means:
J = 3L - 1
Now just solve these
Offline
How do u solve 6J + 5L = 63 ????
Well, you are not solving ONLY that equation -- that equation has *2* unknowns, so you cant solve it by itself.
you are solving *both equations simultaneously*, 6J + 5L = 63 AND J = 3L - 1.
So here is what you do:
We know that 6J + 5L = 63
But we know also that J = 3L - 1
So substitute this second fact about J into the first equation:
6(3L - 1) + 5L = 63
18L - 6 + 5L = 63
23L = 69
L = 3
Now you can go back to either equation and get J.
Offline
ty so much u helped me alot. :D:D
You're welcome.
Offline
Pages: 1