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#1 2006-08-13 10:10:07

dansmark
Member
Registered: 2006-08-08
Posts: 4

Arc to arc calculation (This time with a picture)

I have an arc starting at 0,0 (x=0 & y=0) call this "P1". (counter-clockwise)
The raidus is 1329.0000000
The start angle is 68.45736452
The end angle is 90.00000000
The arc-length is 499.69060185

Also from "P1" horizontally back to the left (angle=180.000000), to a vertical 90 degree line from the end-angle of the 1st arc is 488.0000000 long.
This is how I found my starting point (P1) on the 1st arc.

At the start-angle (P1) a vertical line is 28.875000 long.  (This length will never change)
Angle = 90.0000000
At the end of this line (call this "P2") is the start of another arc going counter-clockwise.
The radius is 77.15944660  (This radius will never change)

Back to the center-point of the arc is:
The Angle in XY Plane = 277.43909137 (from "P2")
Delta X = 9.99000000
Delta Y = -76.51000000

I need a calculation to find the intersection of these 2 arcs.  (in terms a dummy like me can understand)

I hope someone can help!

Thanks,
Dan

View Image: ARC-TO-ARC.jpg View Image: ARC-TO-ARC2.jpg

Last edited by dansmark (2006-08-14 12:46:47)

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#2 2006-08-17 12:49:44

dansmark
Member
Registered: 2006-08-08
Posts: 4

Re: Arc to arc calculation (This time with a picture)

Is this arc-to-arc math question calcuable?
Are there other bits of info needed to find the answer?

It looks simple to me, but then I don't presume to have the answer...

Any takers?

Thanks,
Dan

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