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## #1 2006-07-25 23:45:36

coolwind
Member
Registered: 2005-10-30
Posts: 30

70=T+c
110=T+ce^(K/2)
145=T+ce^K

solve T = ?

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## #2 2006-07-26 07:57:57

numen
Member
Registered: 2006-05-03
Posts: 115

### Re: How to solve this eqation?

1) First, solve for K using your second equation:

2) Now, note that T=70-c and our K above, use your third equation:

Move over 70, and use that (110-T)/c = (c+40)/c (which you can get from 110=T+c+40 in equation 2)

But e^ln(a)=a, so

Which gives c=-320.

3) So T=70-c=70+320=390.

Last edited by numen (2006-07-26 07:59:42)

Bang postponed. Not big enough. Reboot.

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## #3 2006-08-12 09:12:39

fusilli_jerry89
Member
Registered: 2006-06-23
Posts: 86

### Re: How to solve this eqation?

where does the 'e' dissapear off to?

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## #4 2006-08-12 09:39:34

Zhylliolom
Real Member
Registered: 2005-09-05
Posts: 412

### Re: How to solve this eqation?

Last edited by Zhylliolom (2006-08-12 09:39:53)

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