Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**fusilli_jerry89****Member**- Registered: 2006-06-23
- Posts: 86

does anyone know how to get this question? I got pi/2 and 3pi/3.

√2 sin² -sin = 0 Solve for values of sin. 0<x<2pi

Offline

**Ricky****Moderator**- Registered: 2005-12-04
- Posts: 3,791

Is it sin(x) for each?

sin(x) (√2sin²x - 1) = 0

sin(x) = 0 or sin²x = √2/2

x = 0, pi for the first, and sinx = √√2 / √2 which is 2^(3/4) / 2

"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."

Offline

**Kurre****Member**- Registered: 2006-07-18
- Posts: 280

fusilli_jerry89 wrote:

3pi/3.

3pi/3=Pi

Offline

**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

Ricky wrote:

sin(x) (√2sin²x - 1) = 0

Its actually

Thus the solutions are

*Last edited by JaneFairfax (2007-02-28 17:52:30)*

Offline

Pages: **1**