You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

get the number which is divdd by 2 / 3 / 4 / 5 / 6 / 7 / 8 / 9 with a remain 1 !

i got the number its 5251 but the question how can we calculate that !?

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

Offline

**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

sorry i forgot to say its less than 3000

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

Offline

**Ricky****Moderator**- Registered: 2005-12-04
- Posts: 3,791

In what order? For divison, that matters.

"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."

Offline

**Pi Man****Guest**

2521.

To find the Least Common Multiple of two or more numbers, first get the prime factors of each of the numbers.

2 = 2

3 = 3

4 = 2 ** 2 (2 raised to the 2nd power)

5 = 5

6 = 2 * 3

7 = 7

8 = 2 ** 3 (2 raised to the 3rd power)

9 = 3 ** 3 (3 raised to the 2nd power)

Then look at each of the prime factors (2, 3, 5, and 7) and determine the highest "power" for each one. For 2, it's 3 (8 is 2 to the 3rd power). For 3, it's 2 (9 is 3 to the 2nd power). For 5 and 7, it's one. Now multiple all of these together. (2**3) * (3**2) * 5 * 7 = 2520. You want to have a remainder of 1, so add one to it.

2521 / 2 = 1260 with Remainer of 1

2521 / 3 = 840 R1

2521 / 4 = 630 R1

2521 / 5 = 504 R1

2521 / 6 = 420 R1

2521 / 7 = 360 R1

2521 / 8 = 315 R1

2521 / 9 = 280 R1

2521 / 10 = 252 R1

**RauLiTo****Member**- Registered: 2006-01-11
- Posts: 142

brilliant PI MAN !!! u r really creative

thanks alot

ImPo$$!BLe = NoTH!nG

Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...

Offline

**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,306

2520 is found on an Ancient Egyptian temple. Archaeologists infer that Ancient Egyptians were so good at math!

for 2520 can divide 1 to 10 and is the smallest natural number who could do this.

*Last edited by George,Y (2006-06-24 00:53:43)*

**X'(y-Xβ)=0**

Offline

Pages: **1**