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**davit****Guest**

got a problem i need help with in coordinat geometry i have lines 3x-y=13, and 3x-4y=25 that intercept at point M. and line 4x+3y=12 i need to find the equation of the line parallel to 4x+3y=12 and passes through poin M i got a little less than an hour please help

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 23,107

davit,

solve the equations 3x-y=13 and 3x-4y=25.

You get the point of intersection.

That is M (3,-4).

The slope of the line 4x+3y=12 is -4/3.

Hence the equation of the line parallel to 4x+3y=12 would also have the same slope, that is -4/3.

Equation of the line passing through (3,-4)and having slope (-4/3) is given by

(y-y1)=m(x-x1) where m is the slope.

Therefore,

y+4=-4/3(x-3)

3y+12=-4x+12

4x+3y=0.

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