got a problem i need help with in coordinat geometry i have lines 3x-y=13, and 3x-4y=25 that intercept at point M. and line 4x+3y=12 i need to find the equation of the line parallel to 4x+3y=12 and passes through poin M i got a little less than an hour please help
solve the equations 3x-y=13 and 3x-4y=25.
You get the point of intersection.
That is M (3,-4).
The slope of the line 4x+3y=12 is -4/3.
Hence the equation of the line parallel to 4x+3y=12 would also have the same slope, that is -4/3.
Equation of the line passing through (3,-4)and having slope (-4/3) is given by
(y-y1)=m(x-x1) where m is the slope.
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