Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2006-05-15 09:13:07

Registered: 2005-12-12
Posts: 13


10) In ΔRST, the measure of  angle S is 142°. the length of line RS is 10. Find the length of the altitude from vertex R.

please help
greatly appreciated!!!


#2 2006-05-15 18:46:32

Registered: 2006-05-14
Posts: 29

Re: Triangles

ΔRST is not  one an only:(

I'm from Beijing China.


#3 2006-05-15 22:48:44


Re: Triangles

This is a complex problem - one which scientists have pondered over for years. I have recently discovered the truth, the solution to the problem.

As I was playing football with acquantinces, I realized that the ball I was playing with, was in fact a spherical shape. I delved further into this discovery and realized that it was a 360 degree shape. I took this one step furhter and realized that the same concept applied to all shapes and that the sum of all angles in a triangle is 180 degrees. So back to your problem:

180/3 and R is 142 that means that the sum of ST is 180-142.
So S is the square root of the altitude of the vertex of the squared root of the sum.

Evident as it now may be, I will spell it out to you. The answer is 16.

Yours sincerely,
Professor Adam Eugene Cornvy III. At the University of Oxbridge.

#4 2006-05-15 23:29:33

Registered: 2005-06-28
Posts: 24,038

Re: Triangles

I tried to make a diagram of the triangle in the problem. The altitude from vertex R lies outside the triangle!
Let the altitude from vertext R meet ST at point P.
Angle RSP 180 - Angle RST = 180 - 142= 38 degrees

Sin (Angle RSP) = PR/RS
Sin 38 = PR/RS,
we know RS = 10
Therefore, PR = 10 sin 38 = 10(0.61566)=6.1566


It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi. 

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.


Board footer

Powered by FluxBB