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#1 2006-04-06 11:16:47

Hrslvr1612
Member
Registered: 2005-12-12
Posts: 13

I need help BIG TIME!!

This might sound easy but im lost!! I dont understand these at all!!!


This is what it says...

Hint for Problems 6 and 7 : Let radius of the circle be 1 unit.
6. A circle is inscribed in a square. What fraction of the area of the square is taken up by the circle?

7. A square is inscribed in a circle. What fraction of the area of the circle is taken up by the square?

PLEASE HELP!!!

THANK YOU SOOOOOO MUCH!

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#2 2006-04-06 11:34:27

ryos
Member
Registered: 2005-08-04
Posts: 394

Re: I need help BIG TIME!!

6. The fraction of the area of the square taken up by the circle is just the ratio of the area of the circle to the area of the square. We know that the areas to be:
πr² = π1² = π
s² = 2² = 4

Answer: π/4., or roughly 3/4.

7. The diagonal of the square will be a diameter of the circle. If the radius is one, the diameter is 2, and we can find the length of the side by trigonometry:

s = 2cos(45) = sqrt(2)

The area is s², or 2. The ratio of their areas is 2/π, or about 2/3. This is the answer.


El que pega primero pega dos veces.

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#3 2006-04-06 11:38:59

Hrslvr1612
Member
Registered: 2005-12-12
Posts: 13

Re: I need help BIG TIME!!

thanks
but im afraid the second one is wrong i looked it up in the back of the book and the answer is 100/157

how would i get that

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#4 2006-04-06 12:55:56

George,Y
Member
Registered: 2006-03-12
Posts: 1,379

Re: I need help BIG TIME!!

2/π ≈ 2/3.14 =200/314=100/157

Last edited by George,Y (2006-04-06 12:57:20)


X'(y-Xβ)=0

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#5 2006-04-06 14:03:39

Hrslvr1612
Member
Registered: 2005-12-12
Posts: 13

Re: I need help BIG TIME!!

awesome thank you so much!!

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#6 2008-04-17 13:53:56

clah
Guest

Re: I need help BIG TIME!!

why do you put 2/

#7 2008-04-17 14:08:48

ASD
Guest

Re: I need help BIG TIME!!

why do you need to put 2/

#8 2008-04-17 14:17:16

LuisRodg
Real Member
Registered: 2007-10-23
Posts: 322

Re: I need help BIG TIME!!

The area of the square is 2. The area of the circle is pi. The ratio is 2/pi

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