What is the largest power k such as 3^k divides easily into 40? With out anyremainders?
e. none of these
I know a can't be right as 40 is to even of a number to be that only.
but do I use the k like tha other problem with 1/2^3, 1/2^4...and so on? Or is there another one???
I think you need to replace k with those numbers from a, b, c and d.
3^1 = 3
3^4 = 81
3^13 = 1594323
3^17 = 129140163
Since none of these divide into 40 without a remainder, I'd say the answer is e.
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rickyoswalidow is absolutely right!
3^k is a power of 3 and the factors of this number are 1, 3 and the higher powers of 3 up to 3^(k-1). For a number to be divisible by 40, the number should have three 2s and 5 as prime factors. Since 3^k does not have these prime factors,it is not divisble by 40 for any value of k!
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