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#1 2024-03-20 17:29:35

nycguitarguy
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Registered: 2024-02-24
Posts: 559

Three More Even, Odd or Neither Functions

Determine if each function is even, odd, or neither.


1. f(x) = cuberoot{2x^2 + 1}


f(-x) = cuberoot{2(-x)^2 + 1}


f(-x) = cuberoot{2x^2 + 1}


I say even.


2. h(x) = x/(x^2 - 1)


h(-x) = -x/((-x)^2 - 1)


h(-x) = -x/(x^2 - 1)


I say odd.


3. F(x) = 2x/|x|


F(-x) = 2(-x)/|-x|


F(-x) = -2x/x


F(-x) = -2


Neither even or odd.


You say?

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#2 2024-03-20 20:48:00

Bob
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Registered: 2010-06-20
Posts: 10,205

Re: Three More Even, Odd or Neither Functions

1 and 2 are correct.

Think again about 3.  If x is positive 2x/|x| = 2x/x = 2  If x is negative 2x/|x| = 2x/-x = -2

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-03-21 02:37:13

nycguitarguy
Member
Registered: 2024-02-24
Posts: 559

Re: Three More Even, Odd or Neither Functions

Bob wrote:

1 and 2 are correct.

Think again about 3.  If x is positive 2x/|x| = 2x/x = 2  If x is negative 2x/|x| = 2x/-x = -2

Bob

Understood but this further agrees that the answer is neither.

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#4 2024-03-21 03:49:03

Bob
Administrator
Registered: 2010-06-20
Posts: 10,205

Re: Three More Even, Odd or Neither Functions

Definition:

A function is "odd" when:

−f(x) = f(−x) for all x

In this question f(x) =  2       f(-x) = -2 = -f(x)  This is an odd function.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

Online

#5 2024-03-21 09:07:16

nycguitarguy
Member
Registered: 2024-02-24
Posts: 559

Re: Three More Even, Odd or Neither Functions

Bob wrote:

Definition:

A function is "odd" when:

−f(x) = f(−x) for all x

In this question f(x) =  2       f(-x) = -2 = -f(x)  This is an odd function.

Bob

Thank you very much.

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