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I think the first step is to divide by (x + 2).
This will give me the value of a, b, c, and d.
Yes?
Find the sum of a, b, c, and d if
(x^3 - 2x^2 + 3x + 5)/(x + 2) = ax^2 + bx + c + (d/(x + 2)]
You say?
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agree
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agree
Very good. I will show my work later.
After this question I will be moving on to Section R.7 in the textbook.
Chapter 1 begins real college mathematics. Math is cool. It takes my mind away from the problems of life that try to do me in.
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agree
Drop down 1.
(-2)(1) = -2
(-2) + (-2) = -4
(-2)(-4) = 8
8 + 3 = 11
(-2)(11) = -22
-22 + 5 = -17
From this I get x^2 -4x + 11, remainder -17.
a = 1, b = -4, c = 11 and d = -17
Sum = a + b + c + d
Sum = 1 - 4 + 11 - 17
Sum = -9
You say?
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thats what i get
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thats what i get
Looks good. Like Richie Cunningham played by Ron Roward on Happy Days is known for saying: I'M COOKING WITH GAS.
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