Math Is Fun Forum

sologuitar

Member

Registered: 2022-09-19

Posts: 467

Extra Factor Completely

Copy and paste the link provided to see image.

https://imgur.com/a/qtBeMMK

Bob

Administrator

Registered: 2010-06-20

Posts: 10,196

Re: Extra Factor Completely

I used Wolfram Alpha https://www.wolframalpha.com/input?i=fa … 2+-+x+-+2+

and it has no easy factors.  Are you sure you have it copied correctly?

Bob

---

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

sologuitar

Member

Registered: 2022-09-19

Posts: 467

Re: Extra Factor Completely

I used Wolfram Alpha https://www.wolframalpha.com/input?i=fa … 2+-+x+-+2+

and it has no easy factors.  Are you sure you have it copied correctly?

Bob

Bob,

Yes, the question is exactly as stated in the book.

Here are the instructions:

Factor completely. If the polynomial cannot be factored, say it is prime.

This is question 119 in the textbook.
The textbook answer is (x - 1)(x + 1)(x + 2).

amnkb

Member

Registered: 2023-09-19

Posts: 253

Re: Extra Factor Completely

I used Wolfram Alpha https://www.wolframalpha.com/input?i=fa … 2+-+x+-+2+

and it has no easy factors.  Are you sure you have it copied correctly?

Yes, the question is exactly as stated in the book.

Here are the instructions:

Factor completely. If the polynomial cannot be factored, say it is prime.

This is question 119 in the textbook.
The textbook answer is (x - 1)(x + 1)(x + 2).

if you multiply that back out you get

you factored pairs to get to here

but these dont have common factors so nothing can be pulled out front

i think the book typoed the first minus; it was supposed to be plus

sologuitar

Member

Registered: 2022-09-19

Posts: 467

Re: Extra Factor Completely

I used Wolfram Alpha https://www.wolframalpha.com/input?i=fa … 2+-+x+-+2+

and it has no easy factors.  Are you sure you have it copied correctly?

Yes, the question is exactly as stated in the book.

Here are the instructions:

Factor completely. If the polynomial cannot be factored, say it is prime.

https://i.imgur.com/roSPSKl.jpeg

This is question 119 in the textbook.
The textbook answer is (x - 1)(x + 1)(x + 2).

if you multiply that back out you get

you factored pairs to get to here

but these dont have common factors so nothing can be pulled out front

i think the book typoed the first minus; it was supposed to be plus

I also think there is a typo for this question.
The textbook answer is (x - 1)(x + 1)(x + 2).
It doesn't make sense.