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Hi everyone, i have been asked this question:
distance = s = ut + ½at²
u = initial velocity
a = acceleration
t = time
s = distance
what is the formula for the differential of s with respect to time (ds/dt) ?
(surely s/t is velocity, so the forumla is (u + at) But that can't be right because the whole paper is differentiation. so what do I REALLY have to do)
Please help, Les
You just differentiate ut + ½at² with respect to t.
That gives u + at.
Why did the vector cross the road?
It wanted to be normal.
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