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**Les****Guest**

Hi everyone, i have been asked this question:

distance = s = ut + ½at²

u = initial velocity

a = acceleration

t = time

s = distance

what is the formula for the differential of s with respect to time (ds/dt) ?

(surely s/t is velocity, so the forumla is (u + at) But that can't be right because the whole paper is differentiation. so what do I REALLY have to do)

Please help, Les

**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

You just differentiate ut + ½at² with respect to t.

That gives u + at.

Why did the vector cross the road?

It wanted to be normal.

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