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You are not logged in. #1 20060111 15:34:25
Dice problem revisited, showing numbers 0131ganesh posted this problem a few months ago: #2 20060111 15:42:06
Re: Dice problem revisited, showing numbers 0131Oh yeah, here is my written proof: The numbers 09 must be present at least once to represent the desired numbers 0109. Therefore, 10 of the 12 faces of the two dice are taken. There must also be duplicates of the numbers 02 to represent the tens place in the dates. If 02 were present only once on one die, the other die could only represent 6 out of the 10 numbers need for 0109, 1019, and 2029. To have duplicates of 02, there needs 3 more numbers on the faces of the die. The total number of faces needed is 10 + 3, 13. Because the dice only have 12 faces, the proposed situation is impossible. 