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**Bhavya2****Guest**

In right triangle BAC , A is a right angle. AD is perpendicular to BC.

If BD = 9 cm and DC = 4 cm , can you find the area of triangle ABC.

If yes what is the area

If no why can't we find it out?

**Monox D. I-Fly****Member**- Registered: 2015-12-02
- Posts: 981

The area is 39 cm² because AD is 6 cm.

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**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,208

hi Bhavya2

Welcome to the forum.

I have deleted my answer because it was wrong. Monox D. I-Fly has the right result.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**Monox D. I-Fly****Member**- Registered: 2015-12-02
- Posts: 981

bob bundy wrote:

Monox D. I-Fly: Where did you get 6 from?

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**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,208

hi Monox D. I-Fly

Thanks for the explanation. My answer is completely wrong so I have deleted it. Whoops.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**Monox D. I-Fly****Member**- Registered: 2015-12-02
- Posts: 981

You are welcome.

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**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,208

hi NakulG

19.5? What, the area? I think not.

Monox D. I-Fly wrote:

The area is 39 cm² because AD is 6 cm.

This is correct. half base times height = 0.5 x (9+4) x 6 = 13 x 3 = 39.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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