Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
You are not logged in.
#2 2006-01-07 03:35:13
- Ricky
- Moderator
Offline
Re: integral surface 2..
If x = -1, then:
y = 1 / (1 - 1) = 1 / 0
This is not 0, it is undefined. In this particular equation, it is either negative or positive infinity.
You're just unlucky with the coordinates you picked to graph it.
Try x =
1/4 - 1
1/2 - 1
1 - 1
2 - 1
4 - 1
8 - 1
Do the same for the negative side.
Last edited by Ricky (2006-01-07 03:38:40)
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."