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#1 2006-01-06 23:10:09

3d_guru
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integral surface 2..

hey guys...i've attached a picture with an explanation of my problem. please help

cheers


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#2 2006-01-07 03:35:13

Ricky
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Re: integral surface 2..

If x = -1, then:

y = 1 / (1 - 1) = 1 / 0

This is not 0, it is undefined.  In this particular equation, it is either negative or positive infinity.

You're just unlucky with the coordinates you picked to graph it. 

Try x =

1/4 - 1
1/2 - 1
1    - 1
2    - 1
4    - 1
8    - 1

Do the same for the negative side.

Last edited by Ricky (2006-01-07 03:38:40)


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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