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#1 2014-02-23 10:40:34

ronn
Guest

Value of Fourier series

How can I find out the value of the Fourier series

at t=(2-pi)?

If t=(2-pi) had been a point where the function is continuous I know the value of the Fourier series would be the same as the function but since this a point which is not continuous, how can you find out the value of the Fourier series at that point?

Also note that this is a 2pi-periodic even function, where

f(t) = 0 when 0 < t < pi-2
f(t) = pi when pi-2 < t <pi

(Draw the graph and you will see what I mean by continuous).

Actually for this question, a simple correct answer would do to start with.

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