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**kcleigh2****Member**- Registered: 2005-11-24
- Posts: 13

i have a couple of question for people of they are willing to help me please,

1) the equations connecting the running cost of a piece of apparatus,R,and the number of times it is used in one month,N, are

R=(3N + 15)

----------

8

and

N= 8R

----- - 5

3

use these equations to calculate

a) the value of R when N=27

b) the value of N when R= 42

c) the value of R when N=0

this is really getting to me please help thanks to anyone who can )

*Last edited by kcleigh2 (2005-11-24 12:01:02)*

i am really really really rubbish at maths lol lol lol lol lol lol lol lol lol lol lol lol

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,286

Both the equations are the same!

a) When N=27, R=96/12 = 8.

b) When R=42, N= 8*42/3 - 5 = 112-5 = 107.

c) When N=0, R= 15/8

Character is who you are when no one is looking.

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**kcleigh2****Member**- Registered: 2005-11-24
- Posts: 13

thank you for helping me i wouldnt of known where to start thanks again.

i am really really really rubbish at maths lol lol lol lol lol lol lol lol lol lol lol lol

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