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#1 2013-12-18 05:07:52

Bezoux
Member
Registered: 2013-11-17
Posts: 7

A very peculiar surjection

Hey everyone.
I have a very strange question that I know is true, but seems to be bugging me.


I define
so that it doesn't include 0.
This function is obviously surjective, as in for any y from the codomain there is an x in the domain such that f(x)=y.
Is there a good way to prove it?

Last edited by Bezoux (2013-12-18 05:09:22)

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#2 2013-12-18 05:12:16

anonimnystefy
Real Member
From: Harlan's World
Registered: 2011-05-23
Posts: 16,049

Re: A very peculiar surjection

Shouldn't the domain be

?


“Here lies the reader who will never open this book. He is forever dead.
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
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#3 2013-12-18 05:21:52

Nehushtan
Member
Registered: 2013-03-09
Posts: 957

Re: A very peculiar surjection


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